Soldering and resistors- what went wrong?
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RE: Soldering and resistors- what went wrong? - 3/14/2008 8:07:02 PM
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petrorr
Posts: 201
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The resistor is supposed to go inline on the positive side
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RE: Soldering and resistors- what went wrong? - 3/15/2008 7:47:13 AM
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Onarom
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Crap! I was wondering about that, but when I was wiring up LED's, a diagram showed the resistor on the neg. side. It worked fine for the LED's.
Thanks for the response petrorr. lesson learned!
Amps wouldn't be a problem, right? I don't want to waste another $30...
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RE: Soldering and resistors- what went wrong? - 3/15/2008 10:15:11 PM
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petrorr
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on the halo lights i made for my bike im running 3.1v LEDs with a 220 ohm resistor in line on the positive side to each one of four LEDS....I used a 12v, 0.5A charger to test them before mounting them on the bike and wired them to my parking light with no problems...if I had connected them in series +-+-+-+- then I wouldnt have had to use the resistors cause the LEDs would create their own resistance...Maybe your using the right resistor, just on the wrong lead...Resistors drop the forward voltage comming from your power source to something more tolerable for the application...
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RE: Soldering and resistors- what went wrong? - 3/18/2008 5:38:56 PM
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traitorhound
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well a resistor would work if you knew the current draw of the garage door opener when in use so you could use OHM's law to figure it out. I=V/R and then calculated out the correct resistor for your particular circuit.
In your case I probably would have used a variable voltage regulator and build a steady 3v out. More than likely I would have just soldered leads to a momentary switch to have a remote button and just leave the battery in.
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RE: Soldering and resistors- what went wrong? - 3/27/2008 10:19:02 PM
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sUshI
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delete me!
< Message edited by sUshI -- 3/27/2008 10:34:18 PM >
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RE: Soldering and resistors- what went wrong? - 3/27/2008 10:25:58 PM
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sUshI
Posts: 111
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quote:
ORIGINAL: Onarom
used alligator clips to connet the system to the 12.6v car barrery and... SMOKE!
crap, I just fried a $30 garage door opener
. . . . . . What went wrong?
Im sure you figured it out, but what went wrong was you had to much current flowing..and that voltage drop on that resistor was just that, the voltage of that resistor, you still had the remaining voltage going through the door opener.. you need a bigger resistor..one that will drop like 8 volts..
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RE: Soldering and resistors- what went wrong? - 3/29/2008 11:01:18 AM
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nikos
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A resistor does drop voltage when used in series, but it is a ratio of the resistance of the rest of the circuit. In parallel, resistors don't drop voltage, they are used to split current between the parallel lines. It really all depends on the rest of the circuit...
An LED is an interesting circuit design. It is considered a voltage drop in series, but takes close to negligeable current (in comparison to a resistor that would drop the same current). Anyway, it's not necessarily comparable...
Any battery has a theoretical infinite voltage, so you just dumb down the voltage. You need to spec the resistor correctly (look into ohms law) to ensure that you are getting one that is beefy enough to take the power that is running through it (usually specd in watts).
I would start by trying to measure the resistance through the opener (after the switch). As long as you're bypassing the switch on the opener (you need to do this... see why in the next sentence). The only problem there is if you apply constant power to the open switch, the resistance goes to 'infinite' meaning more voltage and therefore current would be applied to the switch in the opener, and it can fry the switch. If you apply power to the other side of the switch, then you're good. Just dont apply constant power there...
You can then spec out a resistor to use in series with the opener circuit (remember its just a ratio, voltage applied*(opener resistace/total series resistance) = voltage across opener). I would use the resistor before the opener, but it shouldn't matter.
There is a 'better' way, by using a voltage regulator, but I think that would be more expensive...
That's really f'n confusing, but I don't know how to explain it much better...
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RE: Soldering and resistors- what went wrong? - 3/29/2008 12:24:36 PM
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KRUSHER F3
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I've always seen and used resistors on the positive side to reduce voltage, never seen them on the negative side.
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RE: Soldering and resistors- what went wrong? - 3/30/2008 11:01:29 AM
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sUshI
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Resistors are POLARITY free, btw..if you have a series circut..then the current will be the same through all devices, resistors will drop voltage..all the devices in the circut will have the same current flow through them, and depending on the resistance of each device, will determine what voltage drop it will have..but all the voltages in the circut HAVE to equal the total voltage..so, say you have a 12 volt battery (conveniently enough) and you connect a resistor in series ( so, a resistor with 1 of the leads on the positive and 1 on the negative, doesnt freaken matter witch way!! You will have a 12 volt drop across that resistor. if the resistor is say 220 ohms, then the current will be..( using Ohms law..of E=IR...) 12=Ix220 ....I = 12/220 ==54.5mA. I = 54.5mA. So the current flow of this particular circut is 54.5 mA
seris cct, is like a train...chooo chooo!! everything is connected after eachother..1 lead to the next.
parallel is where there's a split between 2 leads..or more than 1 path the current can flow.. so, with ought getting way complicated, remember --Current stays the same in a series circut, period. ( Kirchhoff's current and voltage laws)..go here is you want < facstaff.bucknell.edu/mastascu/eLessonsHTML/Basic/Basic5Kv.html >
Voltage stays the same in a parallel cct. -- Just don't go having combination ccts, then the calculator is coming out...and no one wants to see that mamma jamma..its summertime!!
Nikos, what do you mean by measuring the resistance through the opener, when its open, ( like an open cct, theres no current flow, but all the supply voltage is on that 'open' )?? I don't want to call you out, but I don't understand what your trying to say...it doesnt sound right, but your on the right track...I am a sparky so dont take offense!
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RE: Soldering and resistors- what went wrong? - 3/30/2008 11:03:34 AM
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sUshI
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kpsec.freeuk.com/components/led.htm
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RE: Soldering and resistors- what went wrong? - 3/30/2008 5:27:08 PM
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KRUSHER F3
Posts: 156
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quote:
ORIGINAL: sUshI
Resistors are POLARITY free, btw..if you have a series circut..then the current will be the same through all devices, resistors will drop voltage..all the devices in the circut will have the same current flow through them, and depending on the resistance of each device, will determine what voltage drop it will have..but all the voltages in the circut HAVE to equal the total voltage..so, say you have a 12 volt battery (conveniently enough) and you connect a resistor in series ( so, a resistor with 1 of the leads on the positive and 1 on the negative, doesnt freaken matter witch way!! You will have a 12 volt drop across that resistor. if the resistor is say 220 ohms, then the current will be..( using Ohms law..of E=IR...) 12=Ix220 ....I = 12/220 ==54.5mA. I = 54.5mA. So the current flow of this particular circut is 54.5 mA
seris cct, is like a train...chooo chooo!! everything is connected after eachother..1 lead to the next.
parallel is where there's a split between 2 leads..or more than 1 path the current can flow.. so, with ought getting way complicated, remember --Current stays the same in a series circut, period. ( Kirchhoff's current and voltage laws)..go here is you want < facstaff.bucknell.edu/mastascu/eLessonsHTML/Basic/Basic5Kv.html >
Voltage stays the same in a parallel cct. -- Just don't go having combination ccts, then the calculator is coming out...and no one wants to see that mamma jamma..its summertime!!
Nikos, what do you mean by measuring the resistance through the opener, when its open, ( like an open cct, theres no current flow, but all the supply voltage is on that 'open' )?? I don't want to call you out, but I don't understand what your trying to say...it doesnt sound right, but your on the right track...I am a sparky so dont take offense!
We weren't saying resistors have a positive or negative, we were talking about hooking a resistor to the positive side of an LED or whatever you are hooking it to to make the voltage drop. Hook a resistor to the negative side of an LED and see if it will make a difference, I'll bet it will.
< Message edited by KRUSHER F3 -- 3/30/2008 5:37:04 PM >
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Custom made front LED signals
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Polished rim lips & stator cover
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RE: Soldering and resistors- what went wrong? - 3/30/2008 6:57:13 PM
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amanc96
Posts: 67
Joined: 12/16/2007
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quote:
ORIGINAL: axsys
krusher, it shouldnt make a difference where you put the resistor in the circuit. the resistor will limit the current/voltage no matter if it is hooked up to the positive or negative source. components connected in series carry the same current as each other and each component experiences a voltage drop simultaneously, not one at a time.
try your experiment for yourself, it will be the same no matter where the resistor is, like sushi said. parallel is a little more complicated....
Actually, it will make a difference with an LED. The point of the resistor on an anode side of an LED instead of the cathode side is to limit the current through the LED to make sure you don't burn it up.
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Soldering and resistors- what went wrong? - 
